Answer:
See below
Step-by-step explanation:
Part A:
[tex](x+2)(x+3) = (x+2)(x-3) + y[/tex]
Resolving Parenthesis
[tex]x^2+3x+2x+6=x^2-3x-2x+6+y\\x^2+5x+6 = x^2-5x+6+y[/tex]
Subtracting [tex]x^2[/tex] and 6 to both sides
[tex]5x= -5x+y[/tex]
Adding 5x to both sides
[tex]y = 5x+5x\\y = 10x[/tex]
Comparing it with [tex]y = mx+b[/tex] where m is the slope while b is the y-intercept
So,
Slope = m = 10
Y-intercept = b = 0
Part B:
[tex]x = my+b[/tex]
Subtracting b to both sides
[tex]my = x-b[/tex]
Dividing both sides by m
[tex]y = \frac{x-b}{m}\\ y = \frac{x}{m} - \frac{b}{m}[/tex]
Comparing it with [tex]y = mx+b[/tex] where m is the slope while b is the y-intercept
So,
Slope = m = [tex]\frac{1}{m}[/tex]
Y-intercept = b = [tex]-\frac{b}{m}[/tex]
