Answer:
The area of the triangle is [tex]346.0\ mm^2[/tex]
Step-by-step explanation:
Given
Triangle VWU
Required
Determine the Area of the Triangle
First, we'll solve for the third angle
Angles in a triangle when added equals 180; So
[tex]36 + 24 + <V = 180[/tex]
[tex]60 + <V = 180[/tex]
[tex]<V = 180 - 60[/tex]
[tex]<V = 120[/tex]
Next is to determine the length of VW using Sine Law which goes thus
[tex]\frac{VW}{Sin24} = \frac{34}{Sin36}[/tex] (Because 24 degrees is the angle opposite side VW)
Multiply both sides by Sin24
[tex]SIn24 * \frac{VW}{Sin24} = \frac{34}{Sin36} * Sin24[/tex]
[tex]VW = \frac{34}{Sin36} * Sin24[/tex]
[tex]VW = \frac{34}{0.5878} * 0.4067[/tex]
[tex]VW = 23.5 mm[/tex] (Approximated)
At this stage, we have two known sides and two known angles;
The Area can be calculated as the 1/2 * the products of two sides * Sin of the angle between the two sides
Considering VW and VU
VW = 23.5 (Calculated);
VU = 34 (Given)
The angle between these two sides is 120 (Calculated);
Hence;
[tex]Area = \frac{1}{2} * 23.5 * 34 * Sin120[/tex]
[tex]Area = \frac{1}{2} * 23.5 * 34 * 0.8660[/tex]
[tex]Area = \frac{1}{2} * 691.934[/tex]
[tex]Area = 346.0 mm^2[/tex]
Hence, the area of the triangle is [tex]346.0\ mm^2[/tex]
