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Iron(II) is available to bond with chloride ion. How many of each type of ion will bond to form an ionic compound?

A) 3 iron(II), 1 chloride

B) 2 iron(II), 3 chloride

C) 2 iron(II), 1 chloride

D) 1 iron(II), 2 chloride

Respuesta :

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Answer:

D) 1 iron(II), 2 chloride

Explanation:

Iron II chloride is the compound; FeCl2. It is formed as follows, ionically;

Fe^2+(aq) + 2Cl^-(aq) -----> FeCl2

The formation of one mole of FeCl2 involves the reaction one mole of iron and two moles of chloride ions. This means that in FeCl2, the ratio of iron to chlorine is 1:2 as seen above.

Therefore there is one iron II ion and two chloride ions in each mole of iron II chloride, hence the answer.

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