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Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3 , solve for g(f(0)). (5 points) 2 6 8 9

Respuesta :

chikafujiwara

[tex]f(0)=3(0)+1[/tex]

[tex]f(0)=1[/tex]

[tex]g(1)=\frac{4(1)+2}{3}[/tex]

[tex]g(1)=\frac{4+2}{3}[/tex]

[tex]g(1)=\frac{6}{3}[/tex]

[tex]g(1)=2[/tex]

Hope this helps.

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