Answer: 0.9973 .
Step-by-step explanation:
Given: Weights of students in a junior college follows normal distribution with a mean = 100 lbs and a standard deviation =18 lbs.
Let X denotes the random variable that represents the weights of students .
Then, the probability that a student drawn at random will weigh less than 150 lbs will be :
[tex]P(X<150)=P(\dfrac{X_\mu}{\sigma}<\dfrac{150-100}{18})\\\\=P(Z<2.78 )\ \ \ \ [Z=\dfrac{X_\mu}{\sigma}]\\\\ =0.9973\ \ \ [\text{By p-value table for z}][/tex]
Hence, the e=required probability is 0.9973 .
