Given :
Mass of granite , m = 20 g .
Change in temperature , [tex]\Delta T=29-10=19^oC[/tex].
Specific heat capacity of granite , [tex]C=0.79\ J/g^oC[/tex] .
To Find :
The heat absorbed by granite .
Solution :
We know , heat absorb is given by :
[tex]\Delta H=mC\Delta T\\\\\Delta H=20\times 0.79 \times 19 \ J\\\\\Delta H=300.2\ J[/tex]
Therefore , heat absorb is 300.2 J .
Hence , this is the required solution .
Taking into account the definition of calorimetry, the heat absorbed is 300.2 J.
In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is the amount of heat exchanged by a body without affecting its molecular structure. If you don't change the molecular structure, you don't change the state of aggregation. Since the molecular structure does not change, a change in temperature is observed.
In other words, sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
Replacing in the expression to calculate heat exchanges:
Q= 0.79[tex]\frac{J}{gC}[/tex]× 20 g× 19 C
Solving:
Q= 300.2 J
In summary, the heat absorbed is 300.2 J.
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