The first difference of a sequence is 5, 8, 11, 14,... The sum of the first two terms of the original sequence is 23. Find the first three terms of the original sequence

Respuesta :

Answer:

The first three terms of the original sequence are 9, 14, and 22.

Step-by-step explanation:

From the question,

The first difference of the sequence is 5, 8, 11, 14,... That is,

[tex]T_{2} - T_{1} = 5\\T_{3} - T_{2} = 8\\T_{4} - T_{3} = 11\\T_{5} - T_{4} = 14[/tex]

Where [tex]T_{1}[/tex] is the first term of the original sequence

[tex]T_{2}[/tex] is the second term of the original sequence

[tex]T_{3}[/tex] is the third term of the original sequence etc.

Also, from the question, the sum of the first two terms of the original sequence is 23; that is,

[tex]T_{1} + T_{2} = 23[/tex]

Now, we can find [tex]T_{1}[/tex] and [tex]T_{2}[/tex] by solving the following equations simultaneously

[tex]T_{2} - T_{1} = 5[/tex] .......... (1)

[tex]T_{1} + T_{2} = 23[/tex] ......... (2)

From equation (1)

[tex]T_{2} - T_{1} = 5[/tex]

Then,

[tex]T_{2} = 5 + T_{1}[/tex] .......... (3)

Substitute the value of [tex]T_{2}[/tex] into equation (2)

Then, [tex]T_{1} + T_{2} = 23[/tex] becomes

[tex]T_{1} + 5 + T_{1} = 23\\[/tex]

Then,

[tex]2T_{1} + 5 = 23\\2T_{1} = 23 - 5\\2T_{1} = 18[/tex]

[tex]T_{1} = \frac{18}{2} \\T_{1} = 9[/tex]

Hence, the first term of the original sequence is 9

Now, substitute the value of [tex]T_{1}[/tex] into equation (3)

Then, [tex]T_{2} = 5 + T_{1}[/tex] become

[tex]T_{2} = 5 + 9\\[/tex]

∴[tex]T_{2} = 14[/tex]

Hence, the second term of the original sequence is 14

The third term of the original sequence is given by

[tex]T_{3} - T_{2} = 8[/tex]

Then,

[tex]T_{3} = 8 + T_{2}[/tex]

[tex]T_{3} = 8 + 14\\T_{3} = 22[/tex]

Hence, the third term of the original sequence is 22.

Hence, the first three terms of the original sequence are 9, 14, and 22.

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