Answer:
[tex]\huge\boxed{(4,\ 8)}[/tex]
Step-by-step explanation:
[tex]-10<-2x+6<-2\qquad|\text{subtract 6 from all sides}\\\\-10-6<-2x+6-6<-2-6\\\\-16<-2x<-8\qquad|\text{change the signs}\\\\16>2x>8\qquad|\text{divide all sides by 2}\\\\\dfrac{16}{2}>\dfrac{2x}{2}>\dfrac{8}{2}\\\\8>x>4\to4<x<8\\\\\boxed{x\in(4,\ 8)}[/tex]
