contestada

A wildebeest and a chicken participate in a race over a 2.10 km long course. The wildebeest travels at a speed of 19.0 m/s and the chicken can do 3.30 m/s. The wildebeest runs for 1.680 km and then stops to tease the slow-moving chicken, which eventually passes by. The wildebeest waits for a while after the chicken passes and then runs toward the finish line. Both animals cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?
(b) for how long in time (in s) was the wildebeest stationary?

Respuesta :

Answer:

Explanation:

2.1 km = 2100 m

1.68 km = 1680 m

a ) Time taken by wild beast to travel 1680 m

= 1680 / 19 = 88.42 s

Time taken by wild beast to travel 2100 m

2100 / 19 = 110.52 s

distance travelled by chicken in 88.42 s

= 88.42 x 3.3 = 291.78 s

Its distance from the end point

= 2100 - 291.78 = 1808.22m

b ) Time taken by chicken to travel 2100 m

= 2100 / 3.3 = 636.36 s

Both reach simultaneously so , time of resting by wild beast

= 636.36 - 110.52 = 525.84 s .

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