A set of average city temperatures in october are normally distributed with a mean of 20.6°C and a standard deviation of 2°C. what proportion of temperatures are between 18°C and 20.6°C?

Respuesta :

Answer:

0.4032

Step-by-step explanation:

Answer:

0.4032

Step-by-step explanation:

First, we find the z score of the higher given number (20.6)

z-score equation:

z =  (x – μ)  
          σ

In this case, x is 20.6, μ is 20.6, and σ is 2

20.6-20.6=0

0/2 = 0

0 on a z score table is 0.5000

Next, we find the z-score of the lower given number (18)

μ is still 20.6 and σ is still 2

18-20.6 = -2.6

-2.6 / 2 = -1.3

-1.3 on a z-score table is 0.0968

Finally, we subtract our two z-scores

0.5000 - 0.0968 = 0.4032

Answer: 0.4032