Answer:
[tex]\%Cl=73.13\%[/tex]
Explanation:
Hello.
In this case, we can compute the percent composition of chlorine as shown below:
[tex]\%Cl=\frac{2*m_{Cl}}{M_{C_2H_2Cl_2}}[/tex]
Whereas the atomic mass of chlorine is 35.45 g/mol and the molar mass of C₂H₂Cl₂ is 96.95 g/mol, thus, the percent composition turns out:
[tex]\%Cl=\frac{2*35.45g/mol}{96.95g/mol}*100\%\\\\\%Cl=73.13\%[/tex]
Best regards.
