Answer:
1) Na₃PO₄ + 3 KOH ➙ 3 NaOH + K₃PO₄
2) MgF₂ + Li₂CO₃➙ MgCO₃ + 2 LiF
3) P₄ + 3 O₂➙ 2 P₂O₃
Explanation:
To balance an equation, ensure that the number of atoms of each element is equal on both sides.
Reactants would be those on the left of the arrow while products are on the right of the arrow.
Balance O and H atoms last.
Question 1:
__Na₃PO₄ + __KOH ➙ __NaOH + __K₃PO₄
Reactants: 3Na, 1P, 1K, 5O, 1H
Products: 1Na, 1P, 3K, 5O, 1H
Balance the number of Na:
__Na₃PO₄ + __KOH ➙ 3 NaOH + __K₃PO₄
Reactants: 3Na, 1P, 1K, 5O, 1H
Products: 3Na, 1P, 3K, 7O, 3H
Balance the number of K:
__Na₃PO₄ + 3 KOH ➙ 3 NaOH + __K₃PO₄
Reactants: 3Na, 1P, 3K, 7O, 3H
Products: 3Na, 1P, 3K, 7O, 3H
The equation is now balanced.
Question 2:
__MgF₂ + __Li₂CO₃➙ __MgCO₃ + __LiF
Reactants: 1Mg, 2F, 2Li, 1C, 3O
Products: 1Mg, 1F, 1Li, 1C, 3O
Balance number of Li and F atoms:
__MgF₂ + __Li₂CO₃➙ __MgCO₃ + 2 LiF
Reactants: 1Mg, 2F, 2Li, 1C, 3O
Products: 1Mg, 2F, 2Li, 1C, 3O
The equation is now balanced.
Question 3:
__P₄ + __O₂➙ __P₂O₃
Reactants: 4P, 2O
Products: 2P, 3O
Balance the number of P atoms:
__P₄ + __O₂➙ 2 P₂O₃
Reactants: 4P, 2O
Products: 4P, 6O
Balance the number of O atoms:
__P₄ + 3 O₂➙ 2 P₂O₃
Reactants: 4P, 6O
Products: 4P, 6O
The equation is now balanced.
