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A spy in a speed boat is being chased down a
river by government officials in a faster craft.
Just as the officials’ boat pulls up next to the
spy’s boat, both boats reach the edge of a 5.4
m waterfall. The spy’s speed is 16 m/s and
the officials’ speed is 24 m/s.
How far apart will the two vessels be when
they land below the waterfall? The acceleration of gravity is 9.81 m/s

Answer in units of m.

Respuesta :

V1 =16 m/s and V2 =24 m/s. Constant acceleration = 9.8 m/s. The range for a horizontal drop is R=V1* the square root(2h/g. R1=16 * the square root of 2*5.4/9.8. =16.796 meters. And R2= 24 * the square root of 2*5.4/9.8 = 25.194. R2 - R1 = how far apart the two vessel will be. 25.194 - 16.796 = 8.398 or 8.4 meters

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