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The weights of adult women are approximately normally distributed about a mean of 142 lbs. with a standard
deviation of 14 lbs. If Renee is at the 96 percentile in weight for adult women, then her weight, in lbs. is closest
to

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Answer:

166. 5

Step-by-step explanation:

Given the following :

Mean weight (m) = 142 lbs

Standard deviation (sd) = 14 lbs

Renne = 96 percentile, what is Renne's weight

Using the equation :

Zscore = (score - mean) / standard deviation

96 percentile = 0.96 is equivalent to a Zscore of

1.75

Hence,

1.75 = (score - 142) / 14

14 * 1.75 = score - 142

24.5 = score - 142

24.5 + 142 = score

Score = 166.5

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