A race car moving along a circular track has a centripetal acceleration of 12 m/s. If
the distance between the car and the center of the track is 40 m, what is the speed
of the car?

Respuesta :

Answer:

The speed of the car is 21.91 m/s

Step-by-step explanation:

Centripetal Acceleration

It's the acceleration experienced by an object in a uniform circular motion.

It always points toward the center of rotation and is perpendicular to the linear velocity v.

The magnitude of the centripetal acceleration is:

[tex]\displaystyle a_c=\frac{v^2}{r}[/tex]

Where r is the radius of rotation.

The race car has a centripetal acceleration of [tex]a_c=12 m/s^2[/tex] and the radius of rotation is r=40 m.

We can calculate the speed of the car by solving the above equation for v:

[tex]v=\sqrt{a_c\cdot r}[/tex]

[tex]v=\sqrt{12\cdot 40}[/tex]

[tex]v=\sqrt{480}[/tex]

[tex]v=21.91\ m/s[/tex]

The speed of the car is 21.91 m/s