An element with the valence electron configuration 4s24p4 would form a monatomic ion with a charge of fill in the blank 5 . In order to form this ion, the element will ___ _ electron(s) from/into the _______ subshell(s).

The element in the periodic table/chart that matches with the valence electron configuration is Selenium with full electron configuration of [Ar] 3d^10 4s^2 4P^4 which is a non-metal that is found in group 4 of the periodic table/chart.

Selenium can receive 2 more electrons on the 4p^4 to give a -2(minus 2) ion that is Se^2-.

Selenium can also loose 2 electron from 4s^2 to give a +2 ion that is Se^2+.

Selenium can also loose 2 electrons from 4s^2 and 2 electrons from 4p^4 to form Se^4+.

Selenium can also loose 2 electrons from 4s^2 and 4 electrons from 4p^4 to form Se^6+.

Thus, in order to form a monatomic ion with a charge(we will be making use of the most stable one). Thus, it will gain two more electron since this is easier to become 4s^2 4p^6.

pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-11-23T17:40:45+01:00

The monoatomic ion of this atom is X^2- which is formed by gain of two electrons into the 4p orbital.

The valence electrons in an atom are found on the outermost shells of the atom. The kind of charge on an atom forms depends on the valence electrons.

For an atom that has configuration 4s24p4, it would form a monoatomic ion X^2-. In order to form this ion, it must gain two electrons into the 4p subshell.

Learn more: https://brainly.com/question/11897796

An element with the valence electron configuration 4s24p4 would form a monatomic ion with a charge of fill in the blank 5 . In order to form this ion, the element will _____ ___ electron(s) from/into the _______ subshell(s).

Respuesta :

Otras preguntas

An element with the valence electron configuration 4s24p4 would form a monatomic ion with a charge of fill in the blank 5 . In order to form this ion, the element will ___ _ electron(s) from/into the _______ subshell(s).