0.5 kg ball is at the top of a ramp which is 8 meters high. How much kinetic energy does the ball have at the bottom of the ramp?

A. 4 J

B. 10 J

C. 40 J

D. 400 J

Respuesta :

Answer:

40 J

Explanation:

first let find velocity

from law of conservation of energy

[tex] \sqrt{2gh} = v[/tex]

[tex] \sqrt{2(10)(8)} = v[/tex]

[tex] \\ 12.6 = v[/tex]

[tex]k.e = \frac{1}{2} mv {}^{2} [/tex]

approximately 40J (value of g is 9.8 but here it is 10)