Answer:
1.49×10²³ formula units.
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ formula units. This implies that 1 mole of CaCl2 also contains 6.02×10²³ formula units.
Next, we shall determine the mass of 1 mole of CaCl2. This is illustrated below:
1 mole of CaCl2 = 40.08 + (2×35.45)
= 40.08 + 70.9
= 110.98 g
Finally, we shall determine the number of formu units in 27.4 g of CaCl2. This is illustrated below:
From Avogadro's hypothesis,
110.98 g of CaCl2 also contains 6.02×10²³ formula units.
Therefore, 27.4 g of CaCl2 will contain = (27.4 × 6.02×10²³) / 110.98 = 1.49×10²³ formula units.
Thus, 27.4 g of CaCl2 contains 1.49×10²³ formula units.
