Answer:
0.135 mole of H2.
Explanation:
We'll begin by calculating the number of mole in 3.24 g of Mg. This can be obtained as follow:
Mass of Mg = 3.24 g
Molar mass of Mg = 24 g/mol
Mole of Mg =?
Mole = mass /Molar mass
Mole of Mg = 3.24/24
Mole of Mg = 0.135 mole
Next, we shall write the balanced equation for the reaction. This is illustrated below:
Mg + 2HCl —> MgCl2 + H2
From the balanced equation above,
1 mole of Mg reacted to produce 1 mole of H2.
Finally, we shall determine the number of mole of H2 produced by reacting 3.24 g (i.e 0.135 mole) of Mg. This can be obtained as follow:
From the balanced equation above,
1 mole of Mg reacted to produce 1 mole of H2.
Therefore, 0.135 mole of Mg will also react to produce 0.135 mole of H2.
Thus, 0.135 mole of H2 can be obtained from the reaction.
0.135 mole of H2 can be formed.
The reaction of Mg with HCl is:
→ [tex]Mg(s) +2 HCl(aq) \rightarrow MgCl_2 (aq)+H_2(g)[/tex]
The moles of Hâ‚‚ formed will be:
= [tex]3.24 \ g\times \frac{1 \ mol \ Mg}{24.305 \ g \ Mg}\times \frac{1 \ mol \ H_2}{1 \ mol \ Mg}[/tex]
= [tex]3.24\times 0.04114[/tex]
= [tex]0.135 \ mol \ H_2[/tex]
Thus the above answer is right.
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