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a car begins at rest at a stoplight. After the light turns green, the car begins to accelerate 5 m/s squared over the span of 3.6 seconds. What is the car's displacement over this period of time

Respuesta :

Answer: 9m

Explanation:

Our given:

Acceleration- 5m/s^2

Time- 3.6 seconds

Use the equation d = 1/2 • a • t^2

d = 1/2 • 5m/s^2 • 3.6 secs

d = 2.5m/s^2 • 3.6 secs

d = 9m

I hope this is correct

nuhulawal20

The car's displacement over the given period of time is 32.4 meters.

Given the data in the question;

Since the car begins at rest

  • Initial velocity; [tex]u = 0[/tex]
  • Acceleration ; [tex]a = 5m/s^2[/tex]
  • Time taken; [tex]t = 3.6s[/tex]

Displacement or Distance; [tex]s =\ ?[/tex]

To determine the displacement, we use third equation of motion:

[tex]s = ut + \frac{1}{2}at^2[/tex]

Where s is the displacement, u is initial velocity, a is the acceleration, t is time taken.

We substitute our given values into the equation

[tex]s = [0 * 3.6s] + [ \frac{1}{2} * 5m/s^2 * (3.6s)^2 \\\\s = \frac{1}{2} * 5m/s^2\ *12.96s^2\\\\s = 32.4m[/tex]

Therefore, the car's displacement over the given period of time is 32.4 meters.

Learn more: https://brainly.com/question/1095773

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