Explanation:
Bond forming:
Given species:
Na - Sodium Cl - Chlorine
Na has a valence electron
Cl has 7 valence electron
To form a bond of this nature, there must be a transfer of electrons.
Here, the bond is between a metal and non-metal
The metal is sodium and the non-metal is chlorine;
Na → Na⁺ + e⁻ loss of 1 electron
2,8,1 2,8
isoelectronic with Neon
Cl + e → Cl⁻ gain of one electron
isoelectronic with Argon
Na⁺ + Cl⁻ → Na⁺.Cl⁻
This bond type is an ionic bond
Sodium and chlorine atoms formed ionic bond with each other.
Sodium atom make ionic bond with chlorine atom by transferring one electron that is present in the outermost shell of sodium atom. The loss of electron from the sodium atom leads to a positive charge on sodium atom and becomes cation while on the other hand, the chlorine atom receives that electron which causes negative charge on chlorine and becomes anion. Both atoms have opposite charges which attract each other and cancel their effect to become a neutral compound.
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