Mass of CO₂ = 33 g
Further explanation
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Reaction
CH₄ + 2O₂⇒CO₂ + 2H₂O
mol CH₄ :
[tex]\tt =\dfrac{16}{16}=1[/tex]
mol O₂ :
[tex]\tt =\dfrac{48}{32}=1.5[/tex]
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients
[tex]\tt CH_4:O_2=\dfrac{1}{1}:\dfrac{1.5}{2}=1:0.75[/tex]
Because O₂ ratio smaller then O₂ becomes the limiting reactants
So mol CO₂ from limiting reactants
mol CO₂ :
[tex]\tt \dfrac{1}{2}\times 1.5=0.75[/tex]
mass CO₂ :
[tex]\tt mass=mol\times MW=0.75\times 44=33~g[/tex]
