A bowling ball weighing 25 N is dropped off the top of a 11 m tall building. What is the potential energy with respect to the ground when it has fallen half the height of the building?
a. 25 J b. 2.8 x 102 J c. 11 J d. 1.4 x 102 J

Respuesta :

Answer:

1.4x10²J

Explanation:

Given parameters:

Weight of the bowling ball  = 25N

Height of building  = 11m

Unknown:

Potential energy when it has fallen half the height = ?

Solution:

Potential energy is the energy at rest in a body.

  It is mathematically expressed as;

          P.E   = mgh

m is the mass

g is the acceleration due to gravity

h is the height

  The height here is half of the building;

              h  = [tex]\frac{11}{2}[/tex]m

Now,

    Weight = mg = 25N

So;

        P.E = 25 x [tex]\frac{11}{2}[/tex]   = 1.4x10²J