Given :
Kareem heats a beaker of water to boil. Then he records that the water temperature decreases from 100° C to 19° C in 5 2/5 minutes.
To Find :
What was the charged in temperature each minute.
Solution :
Time taken to reach 19° C :
[tex]T = 5\dfrac{2}{5}= \dfrac{27}{5}\ min[/tex]
Now, change in temperature per minute is given by :
[tex]R =\dfrac{19^{o}-100^o}{\dfrac{27}{5}}\\\\R = -15 \ ^oC/ minute[/tex]
Therefore, the charged in temperature each minute is -15 °C/minute .
Hence, this is the required solution.
