A student is late and running to class. A hall monitor tells them to slow down, so the student slows to a walking speed of 1.4 m/s. It takes the student 3.0 seconds to slow to this speed, due to the student’s -2.5 m/s2 acceleration. What was the student’s initial speed

Respuesta :

Answer:

8.9m/s

Explanation:

Final velocity = initial velocity + acceleration *time

Vf=vi+at

Vf=1.4 m/s

Vi=?

A=-2.5m/s^2

T=3

1.4m/s=vi+(-2.5m/s^2)(3s)

Vi=8.9m/s