Type the correct answer in each box. If necessary, use / for the fraction bar(s).

In this triangle, the product of sin B and tan C is
, and the product of sin C and tan B is
.

Respuesta :

The product of sin B and tan C is c/a

The product of sin C and tan B is b/a

Further explanation

We can use

SOH stands for Sine = Opposite ÷ Hypotenuse.

CAH stands for Cosine = Adjacent ÷ Hypotenuse.

TOA stands for Tangent = Opposite ÷ Adjacent.

There is a picture attached

[tex]\tt sin~B=\dfrac{b}{a}\\\\Tan~C=\dfrac{c}{b}\\\\sin~B\times Tan~C=\dfrac{b}{a}\times \dfrac{c}{b}=\dfrac{c}{a}[/tex]

[tex]\tt sin~C=\dfrac{c}{a}\\\\Tan~B=\dfrac{b}{c}\\\\sin~C\times tan~B=\dfrac{c}{a}\times \dfrac{b}{c}=\dfrac{b}{a}[/tex]

Ver imagen ardni313

Answer:

The product of sin B and tan C is (c/a)

The product of sin C and tan B is (b/a)

PLATO