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Assuming that the only lons contributing to the salt content in the Dead sea is Nat
and Cl" ions, calculate the weight of NaCl(s) in 10.0 L of the sea water after
evaporation. The salt content of the Dead sea is reported as 33.7%. Give your
answer in kg.
Answer:

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jufsanabriasa

Answer:

3.37kg of NaCl is the salt content of the dead sea

Explanation:

A concentration of 33.7% means there are 33.7g of NaCl in 100mL of solution.

To solve this question we need to convert 10.0L to mililiters, and then, solve for the mass of NaCl in grams and convert it to kg:

Volume in milliliters:

10.0L * (1000mL / 1L) = 10000mL

Mass of NaCl:

10000mL * (33.7g NaCl / 100mL) = 3370g NaCl

In kg:

3370g * (1kg / 1000g) =

3.37kg of NaCl is the salt content of the dead sea

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