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The cafeteria offers two snack options as shown in the table. Out of 18
students, 8 students choose Option B and the rest choose Option A. If the
total cost of option A is the same as the option B, what is the price of a
carton of milk?”

Respuesta :

Answer:69,420

Step-by-step explanation:

9+10=21

The price of a carton of milk is $1.00

The given parameters are:

  • Number of students, n = 18
  • Option A = 8

Since 8 chose option A, it means that 10 would choose option B

So, the equation that represents when both price are equal is:

[tex]8(2x + 0.5) = 10(x + 1)[/tex]

Where

2x + 0.5 represents the unit price of option A

x + 1 represents the unit price of option B

Open the brackets

[tex]16x + 4 = 10x + 10[/tex]

Collect like terms

[tex]16x - 10x = 10 - 4[/tex]

Evaluate the like terms

[tex]6x = 6[/tex]

Divide

[tex]x = 1[/tex]

Hence, the price of a carton of milk is $1.00

Read more about equivalent equations at:

https://brainly.com/question/2972832