Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2
[tex]8y-14=y+35\\8y-y=35+14\\7y=49[/tex]
Dividing both sides by 7
[tex]\frac{7y}{7}=\frac{49}{7}\\y=7[/tex]
Putting y=7 in Eqn 1
[tex]x=8(7)\\x=56[/tex]
Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
