g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approximately 98 cm/s. The blood volume traverses the aortic arch, exiting with the same speed but opposite direction. Assume the mass density of the blood is 1060 kg/m3 blood, the aortic arch remains stationary, and that the heart rate is 61 bpm. What is the average force exerted by the blood on the wall of the aorta.

Respuesta :

Answer:

The force is [tex]F = 0.1441 \ N[/tex]

Explanation:

From the question we are told that

   The volume of blood ejected is  [tex]V_b = 65cm^3 = 65*10^{-6} \ m^3[/tex]

    The velocity of the ejected blood is  [tex]v = 98 cm/ s = 0.98 \ m/s[/tex]

    The mass density of blood is  [tex]\rho = 1060 \ kg/m^3[/tex]

    The heart rate is  [tex]R = 61 bpm(beats \ per \ miunite) = \frac{61}{60} = 1.0667\ bps[/tex]

Generally the average force exerted is mathematically represented as

     [tex]F = 2 * \rho * V_b * R * v[/tex]

=>   [tex]F = 2 * 1060 * (65*10^{-6}) *1.0667 * 0.98[/tex]

=>   [tex]F = 0.1441 \ N[/tex]