Answer: [tex](-\infty, -4][/tex]
Curved parenthesis at negative infinity
Square bracket at -4
====================================================
Work Shown:
[tex]5(x+4) \le 0 \\\\x+4 \le \frac{0}{5} \\\\x+4 \le 0 \\\\x \le 0-4 \\\\x \le -4 \\\\[/tex]
The last inequality shown above is the same as saying [tex]-\infty < x \le -4[/tex]
Converting this to interval notation leads to the final answer of [tex](-\infty , -4][/tex]
Note the use of a square bracket at -4 to include this endpoint. We can never include either infinity, so we always use a parenthesis for either infinity.
