Answer:
The answer is "Option e".
Explanation:
Given value:
[tex]\to v_{ph}=277 \ \ \ \ \ \ \ I_{ph} =1200\\\\[/tex]
[tex]vA= v_{Ph} I_{ph} \ \ \ \to for \ single \ phase\\\\=3v_{ph} I_{ph} \ \ \ \ \ \to for \ 3 - \phi \\\\s = 3\times 277 \times 1200 \\\\[/tex]
[tex]=997.200 \ K VA\\\\= 1000 \ k VA[/tex]
