Answer:
Alternative hypothesis:
[tex]\mathbf{H_a = \sigma_1^2 \ne \sigma_2^2}[/tex]
Step-by-step explanation:
Given that:
Sample 1:
Sample size [tex]n_1[/tex] = 10
Sample mean [tex]\overline x_1[/tex] = 79.3
Standard deviation [tex]\sigma_1[/tex] = 22.4
Sample 2:
Sample size [tex]n_2[/tex] = 10
Sample mean [tex]\overline x_2[/tex] = 82.1
Standard deviation [tex]\sigma_2[/tex] = 12.0
To find the alternative hypothesis.
The null and alternative hypothesis can be computed as follows:
Null hypothesis:
[tex]\mathbf{H_o = \sigma_1^2 = \sigma_2^2}[/tex]
Alternative hypothesis:
[tex]\mathbf{H_a = \sigma_1^2 \ne \sigma_2^2}[/tex]
Since, alternative hypothesis is ≠, it shows that it is a two tailed test.