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You roll two die. What is the probability you will roll a 4, then roll a number less than 3?
A) 1/36
B) 1/9
C) 1/6
D) 1/18

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Answer:

B 1/9

Step-by-step explanation:

Because there are 6 sides of a die then your adding 3 to the 6

I think. (please dont hate me if im wrong!!)

The probability that if we will roll a 4, then rolling next a number less than 3 is given by: Option D: 1/18

What is the chain rule in probability for two events?

For two events A and B:

The chain rule states that the probability that A and B both occur is given by:

[tex]P(A \cap B) = P(A)P(B|A) = P(B)P( A|B)[/tex]

Which pair of events are called independent events?

When one event's occurrence or non-occurrence doesn't affect occurrence or non-occurrence of other event, then such events are called independent events.

Symbolically, we have:

Two events A and B are said to be independent iff we have:

[tex]P(A \cap B) = P(A)P(B)[/tex]

  • For this case, let we define two events:
    A = event of rolling a 4 in first roll
  • B = event of rolling a number less than 3 in second roll

Then A and B are independent as their outcomes are not directly related or prone to affect each other assumingly.

Thus, probability of rolling a 4, then rolling a number less than 3 is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

Total number of outcomes for any roll = n(S) = 6

Favorable number of outcomes for event A = n(A) = 1 (since a 4 can occur in 1 way out of 6 results)

Thus, P(A) = n(A)/n(S) = 1/6

And, favorable number of outcomes for event B = n(B) = 2 (since numbers less than 3 are only 1 and 2, so two outcomes possible)

Thus, P(B) = n(B)/n(S) = 2/6

Hence, probability of rolling a 4, then rolling a number less than 3 is:

[tex]P(A \cap B) = P(A)P(B) = \dfrac{1}{6} \times \dfrac{2}{6} = \dfrac{2}{36} = \dfrac{1}{18}[/tex]

Therefore, the probability that if we will roll a 4, then rolling next a number less than 3 is given by: Option D: 1/18

Learn more about probability here:

brainly.com/question/1210781