Answer: The volume of this sample at STP is 15.4 L
Explanation:
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 210 kPa
[tex]P_2[/tex] = final pressure of gas = 101.3 kPa ( at STP)
[tex]V_1[/tex] = initial volume of gas = 9.50 L
[tex]V_2[/tex] = final volume of gas = ? ( at STP)
[tex]T_1[/tex] = initial temperature of gas = 350 K
[tex]T_2[/tex] = final temperature of gas = 273 K ( at STP)
Now put all the given values in the above equation, we get:
[tex]\frac{210\times 9.50}{350}=\frac{101.3\times V_2}{273}[/tex]
[tex]V_2=15.4[/tex]
The volume of this sample at STP is 15.4 L