Answer:
4 kg of sugar would contain [tex] 1.2 \times 10^9 [/tex] crystals.
Step-by-step explanation:
Given that 3kg of sugar contains 9 × 10⁸ crystals, let "x" represent the number of sugar crystals 4kg of sugar would contain.
Thus, set up a proportion as follows:
3 kg : 9 × 10⁸ = 4 kg : x
[tex] \frac{3}{9 \times 10^8} = \frac{4}{x} [/tex]
Solve for x. Cross multiply.
[tex] 3 \times x = 9 \times 10^8 \times 4 [/tex]
[tex] 3x = 36 \times 10^8 [/tex]
[tex] 3x = 3.6 \times 10^9 [/tex]
Divide both sides by 3
[tex] \frac{3x}{3} = \frac{3.6 \times 10^9}{3} [/tex]
[tex] x = 1.2 \times 10^9 [/tex]
4 kg of sugar would contain [tex] 1.2 \times 10^9 [/tex] crystals.
