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An amusement park reduced the admission price to $15.50 per day, but now charges $1.50 per ride. Mark has $26 to spend on admission and rides. Write an algebraic equation to find how many rides Mark can ride in one day.

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Answer:

A + 1.50r = 26.00

Step-by-step explanation:

A is the admission price, which is $15.50. So A = 15.50. Substitute 15.50 for A and subtract 15.50 from each side

    A + 1.50r = 26.00

    15.50 + 1.50r = 26.00

    1.50r = 10.50

Divide each side by 1.50.

    1.50r = 10.50

    r = 7

Mark can ride 7 rides in one day.

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