The change in temperature (ΔT) : 56.14 ° C
Given
Cereal energy = 235,000 J
mass of water = 1000 g
Required
the change in temperature (ΔT)
Solution
Heat can be formulated :
Q = m . c . ΔT
c = specific heat for water = 4.186 J / gram ° C
235000 = 1000 . 4.186 . ΔT
[tex]\tt \Delta T=\dfrac{235000}{1000\times 4.186}=56.14^oC[/tex]