Answer:
Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex] results in a polynomial. After subtracting [tex]4x^2-3x[/tex] from this polynomial the difference is 14
Step-by-step explanation:
The question given is:
Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex] results in a polynomial. After subtracting [tex]4x^2-3x[/tex] from this polynomial the difference is?
First we will Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex]
[tex]7x^2+x+9-(3x^2+4x-5)\\=7x^2+x+9-3x^2-4x+5\\Combining\:like\:terms\\=7x^2-3x^2+x-4x+9+5\\=4x^2-3x+14[/tex]
So, the polynomial we get is: [tex]4x^2-3x+14[/tex]
Now, subtracting [tex]4x^2-3x\: from\: 4x^2-3x+14[/tex]
[tex]4x^2-3x+14-(4x^2-3x) \\=4x^2-3x+14-4x^2+3x\\Combining\:like\:terms\\=4x^2-4x^2-3x+3x+14\\=14[/tex]
The difference is 14
So, Subtracting [tex]3x^2+4x-5[/tex] from [tex]7x^2+x+9[/tex] results in a polynomial. After subtracting [tex]4x^2-3x[/tex] from this polynomial the difference is 14
