Answer:
v = 3.08 km/s
Explanation:
Given that,
The angular velocity of the satellite = [tex]\omega=7.27\times 10^{-5} rad/s[/tex]
A satellite is in orbit 36000km above the surface of the earth.
The radius of the earth is 6400 km
Let v is the velocity of the satellite. It can be calculated as :
[tex]v=r\omega\\\\v=(36000\times 10^3+6400\times 10^3)\times 7.27\times 10^{-5}\\\\v=3082.48\ m/s\\\\v=3.08\ km/s[/tex]
So, the velocity of the satellite is 3.08 km/s.
