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6) A sample of water is being cooled according to the formula is given by

C(t)= 80 – 2t, where t represents the number of minutes the water is cooled,

and C measures the corresponding temperature in degrees Centigrade. The

cooling period ends when the water freezes (0°). Determine the relevant

domain and range for this function.

Determine the relevant Domain and relevant Range for this function. Use

interval notation.

Respuesta :

Answer:

Relevant domain: [0 40]

Relevant range: [0 80]

Step-by-step explanation:

We have the following function:

[tex]C(t) = 80 - 2t[/tex]

In which C(t) is the water temperature.

t is the time.

The colling period ends when the water freezes (0°).

So it freezes after t minutes, and t is found when C(t) = 0. So

[tex]C(t) = 80 - 2t[/tex]

[tex]80 - 2t = 0[/tex]

[tex]2t = 80[/tex]

[tex]t = \frac{80}{2}[/tex]

[tex]t = 40[/tex]

Relevant domain:

Input value of the function, which is in minutes. So between 0(initial) and 40(when the water freezes).

Relevant range:

Initial temperature, which is C(0) = 80, until it freezes, 0. So from 0 to 80.

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