The mass of oxygen gas : = 61.98 g
Further explanation
Given
Reaction
Zn(ClO3)2 → ZnCl2 + O2
The mass of zinc chlorate was 150 grams
Required
The mass of oxygen gas
Solution
Balanced equation :
Zn(ClO₃)₂ → ZnCl₂ + 3O₂
mol of Zn(ClO₃)₂ :
= mass : MW
= 150 : 232.29 g/mol
= 0.6457
From equation, mol ratio of Zn(ClO₃)₂ → ZnCl₂ : O₂ = 1 : 3, so mol O₂ :
= 3/1 x mol Zn(ClO₃)₂
= 3/1 x 0.6457
= 1.937
Mass of O₂ :
= mol x MW
= 1.93 x 31.998 g/mol
= 61.98 g
Or we can use equation :
= (150 x 3 x 31.998) : (232.29 x 1) grams
= 14399.1 : 232.29
= 61.98 g
