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At what temperature would 2.10 moles of Nitrogen gas have a pressure of 1.25 atm and in a 25.0 L tank? (Hint: R = 0.082 L atm K−1 mol−1)

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lucky75

Given :-

  • Moles = 2.10

  • Gas = Nitrogen

  • Pressure = 1.25 atm

  • Volume = 25L

To Find :-

  • Temperature

Solution :-

As we know that

PV = nRT

Here,

  • P = Pressure
  • V = Volume
  • n = Moles
  • T = Temperature

According to the question,

  • 1.25 × 25 = 2.1 × 0.082 × T
  • 31.25 = 2.1 × 0.082 × T
  • 31.25 = 1.722T
  • 31.25/0.1722 = T
  • 181 ≈ T

Temperature is 181 K

  • [tex]\large\fbox{181 K}[/tex]

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