a uniform beam 6.0 metre long and weighing 4kg rests on support at p and q placed left and right 1.0 metres from each end of the beam weights of mass 10 kg and 8kg are placed near p and q respectively one each end of the beam.calculate the reaction at p and q?

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Answer:

Explanation:

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Answer:

p and q are 4.0 m apart

moments around q

4 p = (10 * 5) + (4 * 2) - (8 * 1)

p = 12.5

Rp = 12.5 g

moments around p

4 q = (8 * 5) * (4 * 2) - (10 * 1)

q = 9.5

Rq = 9.5 g

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Explanation: