Answer:
2 real roots and 1 imaginary roots
Step-by-step explanation:
f(x) = [tex](x-a)(x-b)^{2} (x^{2}+c)[/tex]
There are only 2 real roots and one imaginary roots.
Separate the equation into sections because the function is a multiplication with no outside sum or substraction:
Real Roots:
[tex](x-a)[/tex] = 0 when x = a
[tex](x-b)^{2}[/tex] = 0 when x = b
Imaginary roots:
[tex](x^{2}-c)[/tex] = 0 when x = [tex]\sqrt{-c}[/tex]
