Answer:
1.40 moles of H₂SO₄.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below below:
2Al + 3H₂SO₄ —> Al₂(SO₄)₃ + 3H₂
From the balanced equation above,
2 moles of Al reacted with 3 moles of H₂SO₄.
Finally, we shall determine the number of mole of H₂SO₄ required to react with
0.93 moles of Al. This can be obtained as follow:
From the balanced equation above,
2 moles of Al reacted with 3 moles of H₂SO₄.
Therefore, 0.93 moles of Al will react with = (0.93 × 3)/2 = 1.40 moles of H₂SO₄.
Thus, 1.40 moles of H₂SO₄ is needed for the reaction.
