Answer: [tex]33.31\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]
and 11.06 moles of Flourine
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]OF_2[/tex] contains= [tex]6.022\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]
Thus 5.53 moles of [tex]OF_2[/tex] contains=[tex]\frac{6.022\times 10^{23}}{1}\times 5.53=33.31\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]
1 mole of [tex]OF_2[/tex] contains= 2 moles of Flourine
5.53 moles of [tex]OF_2[/tex] contains=[tex]\frac{2}{1}\times 5.53=11.06[/tex] moles of Flourine
