Respuesta :
Answer:
120 W lightbulb
Explanation:
Let the two lightbulb be A and B respectively.
Given the following data;
Power A = 120W
Power B = 90W
Voltage = 120V
To find the current flowing through each lightbulb;
a. For lightbulb A
Power = current * voltage
120 = current * 120
Current = 120/120
Current = 1 Ampere.
b. For lightbulb B
Current = power/voltage
Current = 90/120
Current = 0.75 Amperes
Therefore, the lightbulb that carries more current is A with 1 Ampere.
The bulb that carries more current is :
- A with 1 Ampere.
Let the two lightbulb be A and B respectively.
Given :
- Power A = 120W
- Power B = 90W
- Voltage = 120V
To find the current flowing through each lightbulb;
a. For lightbulb A
- Power = current * voltage
- 120 = current * 120Current = 120/120
- Current = 1 Ampere.
b. For lightbulb B
- Current = power/voltage
- Current = 90/120
- Current = 0.75 Amperes
Thus, the lightbulb that carries more current is A with 1 Ampere.
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