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The Shanghai maglev train connects Longyang Road to Pudong International Airport, a distance
of 30 km. The journey takes 8 minutes on average. What is the maglev train's average velocity?

Respuesta :

Answer:

v = 225 km/h

Explanation:

Given that,

Distance Longyang Road to Pudong International Airport, d = 30 km

Time, t = 8 minutes

We need to find Maglev train's average velocity. It can be given by total distance covered divided by time taken.

[tex]v=\dfrac{30\ km}{(\dfrac{8}{60})\ h}\\\\v=225\ km/h[/tex]

So, the required speed is 225 km/h.

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