Given:
A figure.
To find:
The area of the figure.
Solution:
Draw a line and divide the figure it two parts as shown in the below figure.
From the figure it is clear that the line divides the given figure it two rectangles with dimensions 3 yd by 4 yd and 4 yd by 7 yd.
Area of a rectangle is
[tex]Area=Length\times width[/tex]
Using this formula, the areas of both rectangles are
[tex]A_1=3\times 4[/tex]
[tex]A_1=12[/tex]
And,
[tex]A_2=7\times 4[/tex]
[tex]A_2=28[/tex]
Now, the area of combined figure is
[tex]A=A_1+A_2[/tex]
[tex]A=12+28[/tex]
[tex]A=40[/tex]
Therefore, the area of given figure is 40 sq yd.
